if(x)=2x+x^2+3(4x)+17

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Solution for if(x)=2x+x^2+3(4x)+17 equation:


Simplifying
if(x) = 2x + x2 + 3(4x) + 17

Multiply fi * x
fix = 2x + x2 + 3(4x) + 17

Remove parenthesis around (4x)
fix = 2x + x2 + 3 * 4x + 17

Multiply 3 * 4
fix = 2x + x2 + 12x + 17

Reorder the terms:
fix = 17 + 2x + 12x + x2

Combine like terms: 2x + 12x = 14x
fix = 17 + 14x + x2

Solving
fix = 17 + 14x + x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'ix'.
f = 17i-1x-1 + 14i-1 + i-1x

Simplifying
f = 17i-1x-1 + 14i-1 + i-1x

Reorder the terms:
f = 14i-1 + 17i-1x-1 + i-1x

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